NECO PHYSICS PRACTICAL ANSWERS

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(2av)
TABULATE
S/N:1,2,3,4,5,6
U(cm):30.00,35.00,40.00,45.00,50.00,55.00
V(cm):25.50,24.50,23.50,22.50,21.50,20.50
M=V/U:0.850,0.700,0.588,0.500,0.430,0.373

(2avi)
Draw the graph

(2bi)
Using 1/f=1/v+1/u
1/20=1/v+1/25
1/20=(25+v)/25v
25v=20(25v+v)
25v=500+20v
5v=500
v=500/5
v=100cm
Image distance =100cm in front of the mirror

(2bii)
Draw the diagram

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(3avii)
Vo=0.35V
TABULATE
S/N:1,2,3,4,5,6
R(ohm):1.0,2.0,3.0,4.0,5.0,6.0
V(v):1.40,1.65,1.80,2.00,2.10,2.15
R^-1(ohm^-1):1.000,0.500,0.333,0.245,0.200,0.167
V^-1(v^-1):0.714,0.606,0.556,0.500,0.476,0.465

(3aviii)
DRAW THE GRAPH

(3aix)
Slope=change inV^-1/Change inR^-1
=(7.6-4.3)/(0.84-0.10)
3.3/0.74
=4.460

(3ax)
I=0.385
I^-1=(0.385)^-1
=2.597

(3axi)
-I ensured tight connections
-I avoided error due to parallax when reading the voltmetre
-I ensured the key is opened after each reading to prevent the cell from running down

(3bi)
Ohm’s law states that the electric current passing through a metallic conductor at constant temperature is directly proportional to the potential difference apllied between its ends

(3bii)
Since I =Total emf/R+r
I=3E/R+3r

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6 Comments

  • Natawa joe June 5, 2017 at 10:27 am Reply

    I need answer

  • paulblink June 5, 2017 at 10:33 am Reply

    pls sir I need answer

  • Oluedo ifeanyi June 5, 2017 at 2:05 pm Reply

    Pls i ll b rityn data processing

  • lkn June 6, 2017 at 12:33 pm Reply

    Plz stop posting practical so late

  • nanfwang dabiem June 7, 2017 at 9:13 am Reply

    well done

  • malel June 7, 2017 at 7:49 pm Reply

    thanks

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