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# 2019 Neco Chemistry Practical Questions And Answers Now Available For Free

Last modified about 1 month ago by . Posted in Neco | NECO CHEMISTRY PRACTICAL ANSWERS
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EXAM TIME: Tuesday 31st may 2019
CHEMISTRY PRACTICAL 10:00am-12:00pm
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===COMPLETED===

(1)
TABULATE
Rough:26.00,2.00,24.00
Average volume of acid used
=1st+2nd+3rd/3
=24.50+24.50+24.50/3
=24.50cm^3

Concentration of A mol/dm^3=Conc g/dm^3/molar mass
Molar mass of H2SO4 =2(1)+32+4(16)
=98g/dm^3

Concentration mol/dm^3=4.90/98
=0.05mol/dm^3

(i)
Using CaVa/CbVb=na/nb
(0.05*24.50)/Cb*25)=1/2
Cb=(0.05*24.50*2)/25
=0.098mol/dm^3

(ii)Concentration of B in g/dm^3=Conc in mol/dm^3*molar mass
Molar mass of NaOH=26+16+1=40g/mol
=0.098mol/dm^3*40g/mol
=3.92g/dm^3

(iii)percentage purity of B=Concentration of pure/concentration of impure *100%
=3.92/4*100%
=98%
Therefore percentage of impurity of B =100-98%
=2%

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(2ai)
Observation: The salt sample dissolves completely
Inference: C is a mixture of soluble salts

(2aii)
Observation: White precipitate insoluble in excess NaOH(aq)
Inference: Ca^2+ present

(2aiii)
Observation: No visible reaction
Inference: Ca^2+ is present

(2aiv)
Observation: Brownish fume is produced
Inference: NO2(g) form, NO3^- present

(2av)
Observation: Formation of brown gas which forms a ring junction with FeSO4
Inference: NO2 form, NO3^- confirmed

(2bi)
Observation: D dissolves completely. Formation of dirty green precipitate insoluble in excess NaOH(aq)
Inference: D is soluble in salt, Fe^2+ present

(2bii)
Observation: Formation of a white precipitate.precipitate remains insoluble in HCl(aq)
Inference: SO3^2-,CO3^2-,SO4^2- present,SO4^2- confirmed

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(3ai)
Diagram

(3aii)
using CAVA=CBVB
=>2 moldm^-3=0.20moldm^-3
VB=2*40 /0.2
=400cm^3
the volume of distilled water required is 400cm^3

(3bi)
Ethanol

====COMPLETED====

1. marvelous john says: 3 years ago Join us on:  