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2019 WAEC GCE Mathematics Obj & Essay Question & Answers Expo

Last modified about 9 hours ago by . Posted in Gce, Waec |

WAEC GCE GCE 2019 Mathematics Obj & Essay Question & Answers Expo.

MATHEMATICS OBJ
1-10: BBDCCBCBAA
11-20: BCBDCDBDDB
21-30: BCBDCBAACA
31-40: AABBDABCCB
41-50: BBBDBCBCDB

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(1a)
Tabulate
X|2|3|4|5|7|
2|4|6|2|6|
3|6|1|7|5|
5|2|7|1|3|
7|6|5|3|1|

(1bi)
n=7,i;e 3 (*)7=5

(1bii)
n(*)n=1, n=3

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(2a)
Given; slant height l = 18.7cm
Diameter, d = 24cm
? = 22/7
But, Curved surface area of cone = ?rl
=?(d/2)l
= 22/7 × 24/2 × 18.7
=9873.6/14 = 705cm²

(2b)
128^x × 2/16^(1-x) = 8?x
= 2^7x × 2/2^4(1-x) = 2³(?x)
= 2^7x + 1/2^4(1-x) = 2^2x
Cross multiply
2^4(1 – x) + 2x = 2^7x + 1
4(1 – x) + 2x = 7x + 1
4 – 4x + 2x = 7x + 1
4 – 2x = 7x + 1
9x = 3
X = 3/9 = 1/3
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(3a)
3?3/2 – 4?2/3 – ?24
=3?3/2 – 4?2/?3 -?6*4
=(3?3/?2 × ?2/?2) – (4?2/?3 × ?3/?3) – 2?6
=3?6/2 – 4?6/3 – 2?6
=(3/2 – 4/3 – 2)?6
=(9 – 8 – 12)?6
= -11/6?6

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(3bi) prob(only one passes) = m passes and N fails or M fails and N passes
Prob (M passes) = 2/3; prob(M fails) = 1 – 2/3 = 1/3
Prob(N passes) = 4/5; prob(N fails) = 1 – 4/5 = 1/5
Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)
= 2/15 + 4/15
= 6/15
= 2/15

(3bii)
prob(at least one passes) = prob(only one passes) + prob(both parties)
= 2/5 + (2/3 × 4/5)
= 2/5 + 8/15
= 6/15 + 8/15
= 14/15

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(4)
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(5)
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(6)
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(8)
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(9i) DRAW THE DIAGRAM
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n (U) = 110
n (P) = 25
n (B) = 45
n (M) = 48
n (Pnm) = 10
n (Bnm) = 8
n (pnBnm) = 5

(9ii) for biology = 45 = 36

(9iii)
x + 14 + 1 + 5 + 5 + 36 + 3 + 35 = 110
x + 25 + 36 + 38 = 110
x = 110 – 99
x = 11

(9b)
15 = 22 + 18 + 2 x 1 + 10 +20/5
15 x 5 = 40 + 2x + 31
45 = 71 + 2x
45 – 71 + 2x
2x/2 = -26/2
X = 13
22, 18, 2x + 1, 10 , 20
For 2x (-B) +1 = -26 +1 = -25
22, 18, -25, 10, 20
-25, 10, 18, 20, 22
The media is 18
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(10)
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(12)
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(13)
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