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WAEC GCE Physics Practical Questions 2018 | Check OBJ & Theory Answers

Last modified about 1 month ago by . Posted in School News |

WAEC GCE Physics Practical Questions 2018 | Check OBJ & Theory Answers.

WAEC | WAEC GCE Physics Practical Questions 2018… This page contains list of GCE Physics labouratory apparatus that will be used for the Nov./Dec. 2018 Physics Practical Examination. Stay focus and study through.


WAEC GCE Physics Practical Questions 2018

WAEC GCE Physics Practical Questions 2018

The West African Examinations Council (WAEC) is an examination board that conducts the West African Senior School Certificate Examination, for University and Jamb entry examination in West Africa countries. … In a year, over three million candidates registered for the exams coordinated by WAEC.

General Certificate Examination (GCE) for November/December Waec Physics alternative to practical paper will be written on Friday, 26th September, 2018 from 9:30am to 12:15 pm.

We made this post to highlight samples of the Specimens, alternative to practical graphs and calculations that was used in the Chem Practical Examination past questions and syllabus.

WAEC GCE Physics Practical Questions 2018

Keep accessing this page as update will be made in a jiffy

(1a)

Pls Tabulate:

xi(cm)|yi(cm)|zi(cm)|W1(Nx10^-2)|W2(Nx10^-2)|u=(w1-w2)(Nx10^-2)|v=(w1-w3)(Nx10-2)

=>1.80|1.50|1.70|3.6|3.00|3.40|0.60|0.20

=>3.80|3.00|3.00|7.6|6.00|6.00|1.60|1.60

=>5.50|4.40|5.00|11.10|8.00|10.00|2.20|1.00

=>7.30|5.90|6.60|14.60|11.80|13.00|2.80|1.40

=>9.20|7.30|8.30|18.40|14.60|16.60|3.80|1.80

=>11.10|8.30|10.00|22.20|16.60|20.00|5.60|2.20

(1b)

Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. Specific gravity usually means relative density with respect to water.

(1bii)

Given volume of solid immersed

Vsi =1/2*30cm³

=15cm³

Density of liquid (water)ew= 1g/cm³

Acceleration due to gravity, g = 10m/s²

Upthrust, U= eVsi g

U= 1000*(15*10^-6)*10

U=15*10-²

U=0.15N

Weight of solid =mg

=EsVs g

given: Es=2.4g/cm³ (2400kg/m³)

Vs=30cm (30*10^-6 m³)

g=10m/s²

Weight, w=30*10^-6*2400*10

=72*10-²

=0.72N

Reading on spring balance =W-U

=0.72-0.15

=0.57N

===============================

(3aiv)

Tabulate pls:

S/n: 1,2,3,4,5,6

R/ohms: 0.00,1.00,2.00,3.00,4.00,5.00

I/A: 3.00,1.00,0.60,0.45,0.35,0.25

P=(E/I) V ohms^-1: 0.500,1.500,2.500,3.333,4.286,6.000

(3vi)

s=Y1-Y2/X2-X1 = 4-2/3.6-1.5

=2/2.1

=0.952

(3vii)

C = 0.5ohm

(3viii)

Resistance

(3ix)

-I ensured that the circuit is open after each reading to maintain the E.M.F of the battery

-I ensured that the Zero Error of the Ammeter is checked and noted

(3bii)

V = 4.5v

R = 4ohms

I = 0.9A

V = I(R+r)

where r = internal resistance

4.5 = 0.9(4+r)

.:. 4+r = 4.5/0.9

4+r = 5

r = 5-4

= 1 ohm.

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2 Responses

  1. Jemel Angelo says:

    Good nd fantastic

    2 weeks ago

    Join us on:

  2. Adeoye Joel says:

    Nice one. hope it is for waec gce aug/sep 2nd series physics alternavie practical 2018

    2 weeks ago

    Join us on:

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